Adam has 900 green and blue stickers.
He sells 30 green stickers and the number of blue stickers becomes 2 times as many as green stickers.
- How many more blue stickers than green stickers does Adam have at first?
- How many less green stickers than blue stickers does Adam have in the end?
|
Green |
Blue |
Before |
1 u + 30 |
2 u |
Change |
- 30 |
No Change |
After |
1 u |
2 u |
(a)
The number of blue stickers remains unchanged.
Total number of stickers at first
= 1 u + 30 + 2 u
= 3 u + 30
3 u + 30 = 900
3 u = 900 - 30
3 u = 870
1 u = 870 ÷ 3 = 290
Number of more blue stickers than green stickers at first
= 2 u - (1 u + 30)
= 2 u - 1 u - 30
= 1 u - 30
= 1 x 290 - 30
= 290 - 30
= 260
(b)
Number of less green stickers than blue stickers in the end
= 2 u - 1 u
= 1 u
= 1 x 290
= 290
Answer(s): (a) 260; (b) 290