Adam has 700 blue and red stickers.
He sells 40 blue stickers and the number of red stickers becomes 5 times as many as blue stickers.
- How many more red stickers than blue stickers does Adam have at first?
- How many less blue stickers than red stickers does Adam have in the end?
|
Blue |
Red |
Before |
1 u + 40 |
5 u |
Change |
- 40 |
No Change |
After |
1 u |
5 u |
(a)
The number of red stickers remains unchanged.
Total number of stickers at first
= 1 u + 40 + 5 u
= 6 u + 40
6 u + 40 = 700
6 u = 700 - 40
6 u = 660
1 u = 660 ÷ 6 = 110
Number of more red stickers than blue stickers at first
= 5 u - (1 u + 40)
= 5 u - 1 u - 40
= 4 u - 40
= 4 x 110 - 40
= 440 - 40
= 400
(b)
Number of less blue stickers than red stickers in the end
= 5 u - 1 u
= 4 u
= 4 x 110
= 440
Answer(s): (a) 400; (b) 440