Adam has 600 green and red stickers.
He sells 60 green stickers and the number of red stickers becomes 5 times as many as green stickers.
- How many more red stickers than green stickers does Adam have at first?
- How many less green stickers than red stickers does Adam have in the end?
|
Green |
Red |
Before |
1 u + 60 |
5 u |
Change |
- 60 |
No Change |
After |
1 u |
5 u |
(a)
The number of red stickers remains unchanged.
Total number of stickers at first
= 1 u + 60 + 5 u
= 6 u + 60
6 u + 60 = 600
6 u = 600 - 60
6 u = 540
1 u = 540 ÷ 6 = 90
Number of more red stickers than green stickers at first
= 5 u - (1 u + 60)
= 5 u - 1 u - 60
= 4 u - 60
= 4 x 90 - 60
= 360 - 60
= 300
(b)
Number of less green stickers than red stickers in the end
= 5 u - 1 u
= 4 u
= 4 x 90
= 360
Answer(s): (a) 300; (b) 360