Adam has 500 blue and red stickers.
He sells 20 blue stickers and the number of red stickers becomes 5 times as many as blue stickers.
- How many more red stickers than blue stickers does Adam have at first?
- How many less blue stickers than red stickers does Adam have in the end?
|
Blue |
Red |
Before |
1 u + 20 |
5 u |
Change |
- 20 |
No Change |
After |
1 u |
5 u |
(a)
The number of red stickers remains unchanged.
Total number of stickers at first
= 1 u + 20 + 5 u
= 6 u + 20
6 u + 20 = 500
6 u = 500 - 20
6 u = 480
1 u = 480 ÷ 6 = 80
Number of more red stickers than blue stickers at first
= 5 u - (1 u + 20)
= 5 u - 1 u - 20
= 4 u - 20
= 4 x 80 - 20
= 320 - 20
= 300
(b)
Number of less blue stickers than red stickers in the end
= 5 u - 1 u
= 4 u
= 4 x 80
= 320
Answer(s): (a) 300; (b) 320