Adam has 300 green and red stickers.
He sells 80 green stickers and the number of red stickers becomes 4 times as many as green stickers.
- How many more red stickers than green stickers does Adam have at first?
- How many less green stickers than red stickers does Adam have in the end?
|
Green |
Red |
Before |
1 u + 80 |
4 u |
Change |
- 80 |
No Change |
After |
1 u |
4 u |
(a)
The number of red stickers remains unchanged.
Total number of stickers at first
= 1 u + 80 + 4 u
= 5 u + 80
5 u + 80 = 300
5 u = 300 - 80
5 u = 220
1 u = 220 ÷ 5 = 44
Number of more red stickers than green stickers at first
= 4 u - (1 u + 80)
= 4 u - 1 u - 80
= 3 u - 80
= 3 x 44 - 80
= 132 - 80
= 52
(b)
Number of less green stickers than red stickers in the end
= 4 u - 1 u
= 3 u
= 3 x 44
= 132
Answer(s): (a) 52; (b) 132