Adam has 600 blue and green stickers.
He sells 70 blue stickers and the number of green stickers becomes 4 times as many as blue stickers.
- How many more green stickers than blue stickers does Adam have at first?
- How many less blue stickers than green stickers does Adam have in the end?
|
Blue |
Green |
Before |
1 u + 70 |
4 u |
Change |
- 70 |
No Change |
After |
1 u |
4 u |
(a)
The number of green stickers remains unchanged.
Total number of stickers at first
= 1 u + 70 + 4 u
= 5 u + 70
5 u + 70 = 600
5 u = 600 - 70
5 u = 530
1 u = 530 ÷ 5 = 106
Number of more green stickers than blue stickers at first
= 4 u - (1 u + 70)
= 4 u - 1 u - 70
= 3 u - 70
= 3 x 106 - 70
= 318 - 70
= 248
(b)
Number of less blue stickers than green stickers in the end
= 4 u - 1 u
= 3 u
= 3 x 106
= 318
Answer(s): (a) 248; (b) 318