Adam has 900 green and blue stickers.
He sells 90 green stickers and the number of blue stickers becomes 4 times as many as green stickers.
- How many more blue stickers than green stickers does Adam have at first?
- How many less green stickers than blue stickers does Adam have in the end?
|
Green |
Blue |
Before |
1 u + 90 |
4 u |
Change |
- 90 |
No Change |
After |
1 u |
4 u |
(a)
The number of blue stickers remains unchanged.
Total number of stickers at first
= 1 u + 90 + 4 u
= 5 u + 90
5 u + 90 = 900
5 u = 900 - 90
5 u = 810
1 u = 810 ÷ 5 = 162
Number of more blue stickers than green stickers at first
= 4 u - (1 u + 90)
= 4 u - 1 u - 90
= 3 u - 90
= 3 x 162 - 90
= 486 - 90
= 396
(b)
Number of less green stickers than blue stickers in the end
= 4 u - 1 u
= 3 u
= 3 x 162
= 486
Answer(s): (a) 396; (b) 486