Adam has 500 blue and red stickers.
He sells 60 blue stickers and the number of red stickers becomes 4 times as many as blue stickers.
- How many more red stickers than blue stickers does Adam have at first?
- How many less blue stickers than red stickers does Adam have in the end?
|
Blue |
Red |
Before |
1 u + 60 |
4 u |
Change |
- 60 |
No Change |
After |
1 u |
4 u |
(a)
The number of red stickers remains unchanged.
Total number of stickers at first
= 1 u + 60 + 4 u
= 5 u + 60
5 u + 60 = 500
5 u = 500 - 60
5 u = 440
1 u = 440 ÷ 5 = 88
Number of more red stickers than blue stickers at first
= 4 u - (1 u + 60)
= 4 u - 1 u - 60
= 3 u - 60
= 3 x 88 - 60
= 264 - 60
= 204
(b)
Number of less blue stickers than red stickers in the end
= 4 u - 1 u
= 3 u
= 3 x 88
= 264
Answer(s): (a) 204; (b) 264