Adam has 200 green and blue stickers.
He sells 20 green stickers and the number of blue stickers becomes 2 times as many as green stickers.
- How many more blue stickers than green stickers does Adam have at first?
- How many less green stickers than blue stickers does Adam have in the end?
|
Green |
Blue |
Before |
1 u + 20 |
2 u |
Change |
- 20 |
No Change |
After |
1 u |
2 u |
(a)
The number of blue stickers remains unchanged.
Total number of stickers at first
= 1 u + 20 + 2 u
= 3 u + 20
3 u + 20 = 200
3 u = 200 - 20
3 u = 180
1 u = 180 ÷ 3 = 60
Number of more blue stickers than green stickers at first
= 2 u - (1 u + 20)
= 2 u - 1 u - 20
= 1 u - 20
= 1 x 60 - 20
= 60 - 20
= 40
(b)
Number of less green stickers than blue stickers in the end
= 2 u - 1 u
= 1 u
= 1 x 60
= 60
Answer(s): (a) 40; (b) 60