Adam has 600 red and blue stickers.
He sells 60 red stickers and the number of blue stickers becomes 4 times as many as red stickers.
- How many more blue stickers than red stickers does Adam have at first?
- How many less red stickers than blue stickers does Adam have in the end?
|
Red |
Blue |
Before |
1 u + 60 |
4 u |
Change |
- 60 |
No Change |
After |
1 u |
4 u |
(a)
The number of blue stickers remains unchanged.
Total number of stickers at first
= 1 u + 60 + 4 u
= 5 u + 60
5 u + 60 = 600
5 u = 600 - 60
5 u = 540
1 u = 540 ÷ 5 = 108
Number of more blue stickers than red stickers at first
= 4 u - (1 u + 60)
= 4 u - 1 u - 60
= 3 u - 60
= 3 x 108 - 60
= 324 - 60
= 264
(b)
Number of less red stickers than blue stickers in the end
= 4 u - 1 u
= 3 u
= 3 x 108
= 324
Answer(s): (a) 264; (b) 324