Adam has 600 green and blue stickers.
He sells 90 green stickers and the number of blue stickers becomes 5 times as many as green stickers.
- How many more blue stickers than green stickers does Adam have at first?
- How many less green stickers than blue stickers does Adam have in the end?
|
Green |
Blue |
Before |
1 u + 90 |
5 u |
Change |
- 90 |
No Change |
After |
1 u |
5 u |
(a)
The number of blue stickers remains unchanged.
Total number of stickers at first
= 1 u + 90 + 5 u
= 6 u + 90
6 u + 90 = 600
6 u = 600 - 90
6 u = 510
1 u = 510 ÷ 6 = 85
Number of more blue stickers than green stickers at first
= 5 u - (1 u + 90)
= 5 u - 1 u - 90
= 4 u - 90
= 4 x 85 - 90
= 340 - 90
= 250
(b)
Number of less green stickers than blue stickers in the end
= 5 u - 1 u
= 4 u
= 4 x 85
= 340
Answer(s): (a) 250; (b) 340