Adam has 400 red and blue stickers.
He sells 70 red stickers and the number of blue stickers becomes 4 times as many as red stickers.
- How many more blue stickers than red stickers does Adam have at first?
- How many less red stickers than blue stickers does Adam have in the end?
|
Red |
Blue |
Before |
1 u + 70 |
4 u |
Change |
- 70 |
No Change |
After |
1 u |
4 u |
(a)
The number of blue stickers remains unchanged.
Total number of stickers at first
= 1 u + 70 + 4 u
= 5 u + 70
5 u + 70 = 400
5 u = 400 - 70
5 u = 330
1 u = 330 ÷ 5 = 66
Number of more blue stickers than red stickers at first
= 4 u - (1 u + 70)
= 4 u - 1 u - 70
= 3 u - 70
= 3 x 66 - 70
= 198 - 70
= 128
(b)
Number of less red stickers than blue stickers in the end
= 4 u - 1 u
= 3 u
= 3 x 66
= 198
Answer(s): (a) 128; (b) 198