Adam has 900 green and red stickers.
He sells 50 green stickers and the number of red stickers becomes 4 times as many as green stickers.
- How many more red stickers than green stickers does Adam have at first?
- How many less green stickers than red stickers does Adam have in the end?
|
Green |
Red |
Before |
1 u + 50 |
4 u |
Change |
- 50 |
No Change |
After |
1 u |
4 u |
(a)
The number of red stickers remains unchanged.
Total number of stickers at first
= 1 u + 50 + 4 u
= 5 u + 50
5 u + 50 = 900
5 u = 900 - 50
5 u = 850
1 u = 850 ÷ 5 = 170
Number of more red stickers than green stickers at first
= 4 u - (1 u + 50)
= 4 u - 1 u - 50
= 3 u - 50
= 3 x 170 - 50
= 510 - 50
= 460
(b)
Number of less green stickers than red stickers in the end
= 4 u - 1 u
= 3 u
= 3 x 170
= 510
Answer(s): (a) 460; (b) 510