Adam has 200 green and blue stickers.
He sells 40 green stickers and the number of blue stickers becomes 4 times as many as green stickers.
- How many more blue stickers than green stickers does Adam have at first?
- How many less green stickers than blue stickers does Adam have in the end?
|
Green |
Blue |
Before |
1 u + 40 |
4 u |
Change |
- 40 |
No Change |
After |
1 u |
4 u |
(a)
The number of blue stickers remains unchanged.
Total number of stickers at first
= 1 u + 40 + 4 u
= 5 u + 40
5 u + 40 = 200
5 u = 200 - 40
5 u = 160
1 u = 160 ÷ 5 = 32
Number of more blue stickers than green stickers at first
= 4 u - (1 u + 40)
= 4 u - 1 u - 40
= 3 u - 40
= 3 x 32 - 40
= 96 - 40
= 56
(b)
Number of less green stickers than blue stickers in the end
= 4 u - 1 u
= 3 u
= 3 x 32
= 96
Answer(s): (a) 56; (b) 96