Adam has 500 blue and green stickers.
He sells 20 blue stickers and the number of green stickers becomes 2 times as many as blue stickers.
- How many more green stickers than blue stickers does Adam have at first?
- How many less blue stickers than green stickers does Adam have in the end?
|
Blue |
Green |
Before |
1 u + 20 |
2 u |
Change |
- 20 |
No Change |
After |
1 u |
2 u |
(a)
The number of green stickers remains unchanged.
Total number of stickers at first
= 1 u + 20 + 2 u
= 3 u + 20
3 u + 20 = 500
3 u = 500 - 20
3 u = 480
1 u = 480 ÷ 3 = 160
Number of more green stickers than blue stickers at first
= 2 u - (1 u + 20)
= 2 u - 1 u - 20
= 1 u - 20
= 1 x 160 - 20
= 160 - 20
= 140
(b)
Number of less blue stickers than green stickers in the end
= 2 u - 1 u
= 1 u
= 1 x 160
= 160
Answer(s): (a) 140; (b) 160