Adam has 200 red and blue stickers.
He sells 50 red stickers and the number of blue stickers becomes 4 times as many as red stickers.
- How many more blue stickers than red stickers does Adam have at first?
- How many less red stickers than blue stickers does Adam have in the end?
|
Red |
Blue |
Before |
1 u + 50 |
4 u |
Change |
- 50 |
No Change |
After |
1 u |
4 u |
(a)
The number of blue stickers remains unchanged.
Total number of stickers at first
= 1 u + 50 + 4 u
= 5 u + 50
5 u + 50 = 200
5 u = 200 - 50
5 u = 150
1 u = 150 ÷ 5 = 30
Number of more blue stickers than red stickers at first
= 4 u - (1 u + 50)
= 4 u - 1 u - 50
= 3 u - 50
= 3 x 30 - 50
= 90 - 50
= 40
(b)
Number of less red stickers than blue stickers in the end
= 4 u - 1 u
= 3 u
= 3 x 30
= 90
Answer(s): (a) 40; (b) 90