Adam has 400 red and blue stickers.
He sells 40 red stickers and the number of blue stickers becomes 5 times as many as red stickers.
- How many more blue stickers than red stickers does Adam have at first?
- How many less red stickers than blue stickers does Adam have in the end?
|
Red |
Blue |
Before |
1 u + 40 |
5 u |
Change |
- 40 |
No Change |
After |
1 u |
5 u |
(a)
The number of blue stickers remains unchanged.
Total number of stickers at first
= 1 u + 40 + 5 u
= 6 u + 40
6 u + 40 = 400
6 u = 400 - 40
6 u = 360
1 u = 360 ÷ 6 = 60
Number of more blue stickers than red stickers at first
= 5 u - (1 u + 40)
= 5 u - 1 u - 40
= 4 u - 40
= 4 x 60 - 40
= 240 - 40
= 200
(b)
Number of less red stickers than blue stickers in the end
= 5 u - 1 u
= 4 u
= 4 x 60
= 240
Answer(s): (a) 200; (b) 240