Adam has 600 blue and green stickers.
He sells 40 blue stickers and the number of green stickers becomes 3 times as many as blue stickers.
- How many more green stickers than blue stickers does Adam have at first?
- How many less blue stickers than green stickers does Adam have in the end?
|
Blue |
Green |
Before |
1 u + 40 |
3 u |
Change |
- 40 |
No Change |
After |
1 u |
3 u |
(a)
The number of green stickers remains unchanged.
Total number of stickers at first
= 1 u + 40 + 3 u
= 4 u + 40
4 u + 40 = 600
4 u = 600 - 40
4 u = 560
1 u = 560 ÷ 4 = 140
Number of more green stickers than blue stickers at first
= 3 u - (1 u + 40)
= 3 u - 1 u - 40
= 2 u - 40
= 2 x 140 - 40
= 280 - 40
= 240
(b)
Number of less blue stickers than green stickers in the end
= 3 u - 1 u
= 2 u
= 2 x 140
= 280
Answer(s): (a) 240; (b) 280