Adam has 200 blue and red stickers.
He buys 40 blue stickers and the number of blue stickers becomes 4 times as many as red stickers.
- How many more blue stickers than red stickers does Adam have at first?
- How many less red stickers than blue stickers does Adam have in the end?
|
Blue |
Red |
Before |
4 u - 40 |
1 u |
Change |
+ 40 |
No change |
After |
4 u |
1 u |
(a)
The number of red stickers remain unchanged.
Total number of stickers at first
= 1 u + 4 u - 40
= 5 u - 40
5 u - 40 = 200
5 u = 200 + 40
5 u = 240
1 u = 240 ÷ 5 = 48
Number of more blue stickers than red stickers at first
= (4 u - 40) - 1 u
= 4 u - 1 u - 40
= 3 u - 40
= 3 x 48 - 40
= 144 - 40
= 104
(b)
Number of less red stickers than blue stickers in the end
= 4 u - 1 u
= 3 u
= 3 x 48
= 144
Answer(s): (a) 104; (b) 144