Adam has 300 red and blue stickers.
He buys 60 red stickers and the number of red stickers becomes 2 times as many as blue stickers.
- How many more red stickers than blue stickers does Adam have at first?
- How many less blue stickers than red stickers does Adam have in the end?
|
Red |
Blue |
Before |
2 u - 60 |
1 u |
Change |
+ 60 |
No change |
After |
2 u |
1 u |
(a)
The number of blue stickers remain unchanged.
Total number of stickers at first
= 1 u + 2 u - 60
= 3 u - 60
3 u - 60 = 300
3 u = 300 + 60
3 u = 360
1 u = 360 ÷ 3 = 120
Number of more red stickers than blue stickers at first
= (2 u - 60) - 1 u
= 2 u - 1 u - 60
= 1 u - 60
= 1 x 120 - 60
= 120 - 60
= 60
(b)
Number of less blue stickers than red stickers in the end
= 2 u - 1 u
= 1 u
= 1 x 120
= 120
Answer(s): (a) 60; (b) 120