Adam has 800 blue and green stickers.
He buys 70 blue stickers and the number of blue stickers becomes 5 times as many as green stickers.
- How many more blue stickers than green stickers does Adam have at first?
- How many less green stickers than blue stickers does Adam have in the end?
|
Blue |
Green |
Before |
5 u - 70 |
1 u |
Change |
+ 70 |
No change |
After |
5 u |
1 u |
(a)
The number of green stickers remain unchanged.
Total number of stickers at first
= 1 u + 5 u - 70
= 6 u - 70
6 u - 70 = 800
6 u = 800 + 70
6 u = 870
1 u = 870 ÷ 6 = 145
Number of more blue stickers than green stickers at first
= (5 u - 70) - 1 u
= 5 u - 1 u - 70
= 4 u - 70
= 4 x 145 - 70
= 580 - 70
= 510
(b)
Number of less green stickers than blue stickers in the end
= 5 u - 1 u
= 4 u
= 4 x 145
= 580
Answer(s): (a) 510; (b) 580