Adam has 800 green and red stickers.
He buys 60 green stickers and the number of green stickers becomes 4 times as many as red stickers.
- How many more green stickers than red stickers does Adam have at first?
- How many less red stickers than green stickers does Adam have in the end?
|
Green |
Red |
Before |
4 u - 60 |
1 u |
Change |
+ 60 |
No change |
After |
4 u |
1 u |
(a)
The number of red stickers remain unchanged.
Total number of stickers at first
= 1 u + 4 u - 60
= 5 u - 60
5 u - 60 = 800
5 u = 800 + 60
5 u = 860
1 u = 860 ÷ 5 = 172
Number of more green stickers than red stickers at first
= (4 u - 60) - 1 u
= 4 u - 1 u - 60
= 3 u - 60
= 3 x 172 - 60
= 516 - 60
= 456
(b)
Number of less red stickers than green stickers in the end
= 4 u - 1 u
= 3 u
= 3 x 172
= 516
Answer(s): (a) 456; (b) 516