Adam has 400 blue and red stickers.
He buys 50 blue stickers and the number of blue stickers becomes 2 times as many as red stickers.
- How many more blue stickers than red stickers does Adam have at first?
- How many less red stickers than blue stickers does Adam have in the end?
|
Blue |
Red |
Before |
2 u - 50 |
1 u |
Change |
+ 50 |
No change |
After |
2 u |
1 u |
(a)
The number of red stickers remain unchanged.
Total number of stickers at first
= 1 u + 2 u - 50
= 3 u - 50
3 u - 50 = 400
3 u = 400 + 50
3 u = 450
1 u = 450 ÷ 3 = 150
Number of more blue stickers than red stickers at first
= (2 u - 50) - 1 u
= 2 u - 1 u - 50
= 1 u - 50
= 1 x 150 - 50
= 150 - 50
= 100
(b)
Number of less red stickers than blue stickers in the end
= 2 u - 1 u
= 1 u
= 1 x 150
= 150
Answer(s): (a) 100; (b) 150