Adam has 500 blue and red stickers.
He buys 80 blue stickers and the number of blue stickers becomes 4 times as many as red stickers.
- How many more blue stickers than red stickers does Adam have at first?
- How many less red stickers than blue stickers does Adam have in the end?
|
Blue |
Red |
Before |
4 u - 80 |
1 u |
Change |
+ 80 |
No change |
After |
4 u |
1 u |
(a)
The number of red stickers remain unchanged.
Total number of stickers at first
= 1 u + 4 u - 80
= 5 u - 80
5 u - 80 = 500
5 u = 500 + 80
5 u = 580
1 u = 580 ÷ 5 = 116
Number of more blue stickers than red stickers at first
= (4 u - 80) - 1 u
= 4 u - 1 u - 80
= 3 u - 80
= 3 x 116 - 80
= 348 - 80
= 268
(b)
Number of less red stickers than blue stickers in the end
= 4 u - 1 u
= 3 u
= 3 x 116
= 348
Answer(s): (a) 268; (b) 348