Adam has 700 green and blue stickers.
He buys 40 green stickers and the number of green stickers becomes 3 times as many as blue stickers.
- How many more green stickers than blue stickers does Adam have at first?
- How many less blue stickers than green stickers does Adam have in the end?
|
Green |
Blue |
Before |
3 u - 40 |
1 u |
Change |
+ 40 |
No change |
After |
3 u |
1 u |
(a)
The number of blue stickers remain unchanged.
Total number of stickers at first
= 1 u + 3 u - 40
= 4 u - 40
4 u - 40 = 700
4 u = 700 + 40
4 u = 740
1 u = 740 ÷ 4 = 185
Number of more green stickers than blue stickers at first
= (3 u - 40) - 1 u
= 3 u - 1 u - 40
= 2 u - 40
= 2 x 185 - 40
= 370 - 40
= 330
(b)
Number of less blue stickers than green stickers in the end
= 3 u - 1 u
= 2 u
= 2 x 185
= 370
Answer(s): (a) 330; (b) 370