Adam has 500 green and red stickers.
He buys 50 green stickers and the number of green stickers becomes 4 times as many as red stickers.
- How many more green stickers than red stickers does Adam have at first?
- How many less red stickers than green stickers does Adam have in the end?
|
Green |
Red |
Before |
4 u - 50 |
1 u |
Change |
+ 50 |
No change |
After |
4 u |
1 u |
(a)
The number of red stickers remain unchanged.
Total number of stickers at first
= 1 u + 4 u - 50
= 5 u - 50
5 u - 50 = 500
5 u = 500 + 50
5 u = 550
1 u = 550 ÷ 5 = 110
Number of more green stickers than red stickers at first
= (4 u - 50) - 1 u
= 4 u - 1 u - 50
= 3 u - 50
= 3 x 110 - 50
= 330 - 50
= 280
(b)
Number of less red stickers than green stickers in the end
= 4 u - 1 u
= 3 u
= 3 x 110
= 330
Answer(s): (a) 280; (b) 330