Adam has 700 blue and green stickers.
He buys 30 blue stickers and the number of blue stickers becomes 4 times as many as green stickers.
- How many more blue stickers than green stickers does Adam have at first?
- How many less green stickers than blue stickers does Adam have in the end?
|
Blue |
Green |
Before |
4 u - 30 |
1 u |
Change |
+ 30 |
No change |
After |
4 u |
1 u |
(a)
The number of green stickers remain unchanged.
Total number of stickers at first
= 1 u + 4 u - 30
= 5 u - 30
5 u - 30 = 700
5 u = 700 + 30
5 u = 730
1 u = 730 ÷ 5 = 146
Number of more blue stickers than green stickers at first
= (4 u - 30) - 1 u
= 4 u - 1 u - 30
= 3 u - 30
= 3 x 146 - 30
= 438 - 30
= 408
(b)
Number of less green stickers than blue stickers in the end
= 4 u - 1 u
= 3 u
= 3 x 146
= 438
Answer(s): (a) 408; (b) 438