Adam has 500 red and blue stickers.
He buys 90 red stickers and the number of red stickers becomes 4 times as many as blue stickers.
- How many more red stickers than blue stickers does Adam have at first?
- How many less blue stickers than red stickers does Adam have in the end?
|
Red |
Blue |
Before |
4 u - 90 |
1 u |
Change |
+ 90 |
No change |
After |
4 u |
1 u |
(a)
The number of blue stickers remain unchanged.
Total number of stickers at first
= 1 u + 4 u - 90
= 5 u - 90
5 u - 90 = 500
5 u = 500 + 90
5 u = 590
1 u = 590 ÷ 5 = 118
Number of more red stickers than blue stickers at first
= (4 u - 90) - 1 u
= 4 u - 1 u - 90
= 3 u - 90
= 3 x 118 - 90
= 354 - 90
= 264
(b)
Number of less blue stickers than red stickers in the end
= 4 u - 1 u
= 3 u
= 3 x 118
= 354
Answer(s): (a) 264; (b) 354