Adam has 100 green and blue stickers.
He buys 50 green stickers and the number of green stickers becomes 5 times as many as blue stickers.
- How many more green stickers than blue stickers does Adam have at first?
- How many less blue stickers than green stickers does Adam have in the end?
|
Green |
Blue |
Before |
5 u - 50 |
1 u |
Change |
+ 50 |
No change |
After |
5 u |
1 u |
(a)
The number of blue stickers remain unchanged.
Total number of stickers at first
= 1 u + 5 u - 50
= 6 u - 50
6 u - 50 = 100
6 u = 100 + 50
6 u = 150
1 u = 150 ÷ 6 = 25
Number of more green stickers than blue stickers at first
= (5 u - 50) - 1 u
= 5 u - 1 u - 50
= 4 u - 50
= 4 x 25 - 50
= 100 - 50
= 50
(b)
Number of less blue stickers than green stickers in the end
= 5 u - 1 u
= 4 u
= 4 x 25
= 100
Answer(s): (a) 50; (b) 100