Adam has 800 green and red stickers.
He buys 40 green stickers and the number of green stickers becomes 4 times as many as red stickers.
- How many more green stickers than red stickers does Adam have at first?
- How many less red stickers than green stickers does Adam have in the end?
|
Green |
Red |
Before |
4 u - 40 |
1 u |
Change |
+ 40 |
No change |
After |
4 u |
1 u |
(a)
The number of red stickers remain unchanged.
Total number of stickers at first
= 1 u + 4 u - 40
= 5 u - 40
5 u - 40 = 800
5 u = 800 + 40
5 u = 840
1 u = 840 ÷ 5 = 168
Number of more green stickers than red stickers at first
= (4 u - 40) - 1 u
= 4 u - 1 u - 40
= 3 u - 40
= 3 x 168 - 40
= 504 - 40
= 464
(b)
Number of less red stickers than green stickers in the end
= 4 u - 1 u
= 3 u
= 3 x 168
= 504
Answer(s): (a) 464; (b) 504