Adam has 300 blue and red stickers.
He buys 90 blue stickers and the number of blue stickers becomes 5 times as many as red stickers.
- How many more blue stickers than red stickers does Adam have at first?
- How many less red stickers than blue stickers does Adam have in the end?
|
Blue |
Red |
Before |
5 u - 90 |
1 u |
Change |
+ 90 |
No change |
After |
5 u |
1 u |
(a)
The number of red stickers remain unchanged.
Total number of stickers at first
= 1 u + 5 u - 90
= 6 u - 90
6 u - 90 = 300
6 u = 300 + 90
6 u = 390
1 u = 390 ÷ 6 = 65
Number of more blue stickers than red stickers at first
= (5 u - 90) - 1 u
= 5 u - 1 u - 90
= 4 u - 90
= 4 x 65 - 90
= 260 - 90
= 170
(b)
Number of less red stickers than blue stickers in the end
= 5 u - 1 u
= 4 u
= 4 x 65
= 260
Answer(s): (a) 170; (b) 260