Adam has 400 blue and green stickers.
He buys 40 blue stickers and the number of blue stickers becomes 4 times as many as green stickers.
- How many more blue stickers than green stickers does Adam have at first?
- How many less green stickers than blue stickers does Adam have in the end?
|
Blue |
Green |
Before |
4 u - 40 |
1 u |
Change |
+ 40 |
No change |
After |
4 u |
1 u |
(a)
The number of green stickers remain unchanged.
Total number of stickers at first
= 1 u + 4 u - 40
= 5 u - 40
5 u - 40 = 400
5 u = 400 + 40
5 u = 440
1 u = 440 ÷ 5 = 88
Number of more blue stickers than green stickers at first
= (4 u - 40) - 1 u
= 4 u - 1 u - 40
= 3 u - 40
= 3 x 88 - 40
= 264 - 40
= 224
(b)
Number of less green stickers than blue stickers in the end
= 4 u - 1 u
= 3 u
= 3 x 88
= 264
Answer(s): (a) 224; (b) 264