Adam has 400 blue and green stickers.
He buys 50 blue stickers and the number of blue stickers becomes 5 times as many as green stickers.
- How many more blue stickers than green stickers does Adam have at first?
- How many less green stickers than blue stickers does Adam have in the end?
|
Blue |
Green |
Before |
5 u - 50 |
1 u |
Change |
+ 50 |
No change |
After |
5 u |
1 u |
(a)
The number of green stickers remain unchanged.
Total number of stickers at first
= 1 u + 5 u - 50
= 6 u - 50
6 u - 50 = 400
6 u = 400 + 50
6 u = 450
1 u = 450 ÷ 6 = 75
Number of more blue stickers than green stickers at first
= (5 u - 50) - 1 u
= 5 u - 1 u - 50
= 4 u - 50
= 4 x 75 - 50
= 300 - 50
= 250
(b)
Number of less green stickers than blue stickers in the end
= 5 u - 1 u
= 4 u
= 4 x 75
= 300
Answer(s): (a) 250; (b) 300