Adam has 200 green and blue stickers.
He buys 60 green stickers and the number of green stickers becomes 4 times as many as blue stickers.
- How many more green stickers than blue stickers does Adam have at first?
- How many less blue stickers than green stickers does Adam have in the end?
|
Green |
Blue |
Before |
4 u - 60 |
1 u |
Change |
+ 60 |
No change |
After |
4 u |
1 u |
(a)
The number of blue stickers remain unchanged.
Total number of stickers at first
= 1 u + 4 u - 60
= 5 u - 60
5 u - 60 = 200
5 u = 200 + 60
5 u = 260
1 u = 260 ÷ 5 = 52
Number of more green stickers than blue stickers at first
= (4 u - 60) - 1 u
= 4 u - 1 u - 60
= 3 u - 60
= 3 x 52 - 60
= 156 - 60
= 96
(b)
Number of less blue stickers than green stickers in the end
= 4 u - 1 u
= 3 u
= 3 x 52
= 156
Answer(s): (a) 96; (b) 156