Adam has 600 blue and green stickers.
He buys 70 blue stickers and the number of blue stickers becomes 4 times as many as green stickers.
- How many more blue stickers than green stickers does Adam have at first?
- How many less green stickers than blue stickers does Adam have in the end?
|
Blue |
Green |
Before |
4 u - 70 |
1 u |
Change |
+ 70 |
No change |
After |
4 u |
1 u |
(a)
The number of green stickers remain unchanged.
Total number of stickers at first
= 1 u + 4 u - 70
= 5 u - 70
5 u - 70 = 600
5 u = 600 + 70
5 u = 670
1 u = 670 ÷ 5 = 134
Number of more blue stickers than green stickers at first
= (4 u - 70) - 1 u
= 4 u - 1 u - 70
= 3 u - 70
= 3 x 134 - 70
= 402 - 70
= 332
(b)
Number of less green stickers than blue stickers in the end
= 4 u - 1 u
= 3 u
= 3 x 134
= 402
Answer(s): (a) 332; (b) 402