Adam has 600 blue and green stickers.
He buys 60 blue stickers and the number of blue stickers becomes 5 times as many as green stickers.
- How many more blue stickers than green stickers does Adam have at first?
- How many less green stickers than blue stickers does Adam have in the end?
|
Blue |
Green |
Before |
5 u - 60 |
1 u |
Change |
+ 60 |
No change |
After |
5 u |
1 u |
(a)
The number of green stickers remain unchanged.
Total number of stickers at first
= 1 u + 5 u - 60
= 6 u - 60
6 u - 60 = 600
6 u = 600 + 60
6 u = 660
1 u = 660 ÷ 6 = 110
Number of more blue stickers than green stickers at first
= (5 u - 60) - 1 u
= 5 u - 1 u - 60
= 4 u - 60
= 4 x 110 - 60
= 440 - 60
= 380
(b)
Number of less green stickers than blue stickers in the end
= 5 u - 1 u
= 4 u
= 4 x 110
= 440
Answer(s): (a) 380; (b) 440