Adam has 2 times as many red stickers as blue stickers.
After he gives away 48 blue stickers,
Adam has 5 times as many red stickers as blue stickers.
- How many more red stickers than blue stickers does Adam have at first?
- How many less blue stickers than red stickers does Adam have in the end?
|
Red |
Blue |
Before |
2 x 5 = 10 u |
1 x 5 = 5 u |
Change |
No Change |
- 48 |
After |
5 x 2 = 10 u |
1 x 2 = 2 u |
(a)
The number of red stickers remains unchanged.
Make the number of red stickers and blue stickers the same using LCM of 2 and 5.
LCM of 2 and 5 = 10
Number of blue stickers that Adam gives away
= 5 u - 2 u
= 3 u
3 u = 48
1 u = 48 ÷ 3 = 16
Number of more red stickers than blue stickers at first
= 10 u - 5 u
= 5 u
= 5 x 16
= 80
(b)
Number of less blue stickers than red stickers in the end
= 10 u - 2 u
= 8 u
= 8 x 16
= 128
Answer(s): (a) 80; (b) 128