Adam has 4 times as many red stickers as blue stickers.
After he gives away 23 blue stickers,
Adam has 6 times as many red stickers as blue stickers.
- How many more red stickers than blue stickers does Adam have at first?
- How many less blue stickers than red stickers does Adam have in the end?
|
Red |
Blue |
Before |
4 x 3 = 12 u |
1 x 3 = 3 u |
Change |
No Change |
- 23 |
After |
6 x 2 = 12 u |
1 x 2 = 2 u |
(a)
The number of red stickers remains unchanged.
Make the number of red stickers and blue stickers the same using LCM of 4 and 6.
LCM of 4 and 6 = 12
Number of blue stickers that Adam gives away
= 3 u - 2 u
= 1 u
1 u = 23
1 u = 23 ÷ 1 = 23
Number of more red stickers than blue stickers at first
= 12 u - 6 u
= 6 u
= 6 x 23
= 138
(b)
Number of less blue stickers than red stickers in the end
= 12 u - 4 u
= 8 u
= 8 x 23
= 184
Answer(s): (a) 138; (b) 184