Adam has 4 times as many red stickers as green stickers.
After he gives away 20 green stickers,
Adam has 9 times as many red stickers as green stickers.
- How many more red stickers than green stickers does Adam have at first?
- How many less green stickers than red stickers does Adam have in the end?
|
Red |
Green |
Before |
4 x 9 = 36 u |
1 x 9 = 9 u |
Change |
No Change |
- 20 |
After |
9 x 4 = 36 u |
1 x 4 = 4 u |
(a)
The number of red stickers remains unchanged.
Make the number of red stickers and green stickers the same using LCM of 4 and 9.
LCM of 4 and 9 = 36
Number of green stickers that Adam gives away
= 9 u - 4 u
= 5 u
5 u = 20
1 u = 20 ÷ 5 = 4
Number of more red stickers than green stickers at first
= 36 u - 9 u
= 27 u
= 27 x 4
= 108
(b)
Number of less green stickers than red stickers in the end
= 36 u - 4 u
= 32 u
= 32 x 4
= 128
Answer(s): (a) 108; (b) 128