Adam has 5 times as many blue stickers as red stickers.
After he gives away 24 red stickers,
Adam has 7 times as many blue stickers as red stickers.
- How many more blue stickers than red stickers does Adam have at first?
- How many less red stickers than blue stickers does Adam have in the end?
|
Blue |
Red |
Before |
5 x 7 = 35 u |
1 x 7 = 7 u |
Change |
No Change |
- 24 |
After |
7 x 5 = 35 u |
1 x 5 = 5 u |
(a)
The number of blue stickers remains unchanged.
Make the number of blue stickers and red stickers the same using LCM of 5 and 7.
LCM of 5 and 7 = 35
Number of red stickers that Adam gives away
= 7 u - 5 u
= 2 u
2 u = 24
1 u = 24 ÷ 2 = 12
Number of more blue stickers than red stickers at first
= 35 u - 7 u
= 28 u
= 28 x 12
= 336
(b)
Number of less red stickers than blue stickers in the end
= 35 u - 5 u
= 30 u
= 30 x 12
= 360
Answer(s): (a) 336; (b) 360