Adam has 2 times as many blue stickers as green stickers.
After he gives away 25 green stickers,
Adam has 3 times as many blue stickers as green stickers.
- How many more blue stickers than green stickers does Adam have at first?
- How many less green stickers than blue stickers does Adam have in the end?
|
Blue |
Green |
Before |
2 x 3 = 6 u |
1 x 3 = 3 u |
Change |
No Change |
- 25 |
After |
3 x 2 = 6 u |
1 x 2 = 2 u |
(a)
The number of blue stickers remains unchanged.
Make the number of blue stickers and green stickers the same using LCM of 2 and 3.
LCM of 2 and 3 = 6
Number of green stickers that Adam gives away
= 3 u - 2 u
= 1 u
1 u = 25
Number of more blue stickers than green stickers at first
= 6 u - 3 u
= 3 u
= 3 x 25
= 75
(b)
Number of less green stickers than blue stickers in the end
= 6 u - 2 u
= 4 u
= 4 x 25
= 100
Answer(s): (a) 75; (b) 100