Adam has 5 times as many red stickers as green stickers.
After he gives away 32 green stickers,
Adam has 7 times as many red stickers as green stickers.
- How many more red stickers than green stickers does Adam have at first?
- How many less green stickers than red stickers does Adam have in the end?
|
Red |
Green |
Before |
5 x 7 = 35 u |
1 x 7 = 7 u |
Change |
No Change |
- 32 |
After |
7 x 5 = 35 u |
1 x 5 = 5 u |
(a)
The number of red stickers remains unchanged.
Make the number of red stickers and green stickers the same using LCM of 5 and 7.
LCM of 5 and 7 = 35
Number of green stickers that Adam gives away
= 7 u - 5 u
= 2 u
2 u = 32
1 u = 32 ÷ 2 = 16
Number of more red stickers than green stickers at first
= 35 u - 7 u
= 28 u
= 28 x 16
= 448
(b)
Number of less green stickers than red stickers in the end
= 35 u - 5 u
= 30 u
= 30 x 16
= 480
Answer(s): (a) 448; (b) 480