Adam has 4 times as many blue stickers as red stickers.
After he gives away 27 red stickers,
Adam has 7 times as many blue stickers as red stickers.
- How many more blue stickers than red stickers does Adam have at first?
- How many less red stickers than blue stickers does Adam have in the end?
|
Blue |
Red |
Before |
4 x 7 = 28 u |
1 x 7 = 7 u |
Change |
No Change |
- 27 |
After |
7 x 4 = 28 u |
1 x 4 = 4 u |
(a)
The number of blue stickers remains unchanged.
Make the number of blue stickers and red stickers the same using LCM of 4 and 7.
LCM of 4 and 7 = 28
Number of red stickers that Adam gives away
= 7 u - 4 u
= 3 u
3 u = 27
1 u = 27 ÷ 3 = 9
Number of more blue stickers than red stickers at first
= 28 u - 7 u
= 21 u
= 21 x 9
= 189
(b)
Number of less red stickers than blue stickers in the end
= 28 u - 4 u
= 24 u
= 24 x 9
= 216
Answer(s): (a) 189; (b) 216