Adam has 3 times as many blue stickers as green stickers.
After he gives away 48 green stickers,
Adam has 5 times as many blue stickers as green stickers.
- How many more blue stickers than green stickers does Adam have at first?
- How many less green stickers than blue stickers does Adam have in the end?
|
Blue |
Green |
Before |
3 x 5 = 15 u |
1 x 5 = 5 u |
Change |
No Change |
- 48 |
After |
5 x 3 = 15 u |
1 x 3 = 3 u |
(a)
The number of blue stickers remains unchanged.
Make the number of blue stickers and green stickers the same using LCM of 3 and 5.
LCM of 3 and 5 = 15
Number of green stickers that Adam gives away
= 5 u - 3 u
= 2 u
2 u = 48
1 u = 48 ÷ 2 = 24
Number of more blue stickers than green stickers at first
= 15 u - 5 u
= 10 u
= 10 x 24
= 240
(b)
Number of less green stickers than blue stickers in the end
= 15 u - 3 u
= 12 u
= 12 x 24
= 288
Answer(s): (a) 240; (b) 288