Adam has 2 times as many green stickers as blue stickers.
After he gives away 45 blue stickers,
Adam has 3 times as many green stickers as blue stickers.
- How many more green stickers than blue stickers does Adam have at first?
- How many less blue stickers than green stickers does Adam have in the end?
|
Green |
Blue |
Before |
2 x 3 = 6 u |
1 x 3 = 3 u |
Change |
No Change |
- 45 |
After |
3 x 2 = 6 u |
1 x 2 = 2 u |
(a)
The number of green stickers remains unchanged.
Make the number of green stickers and blue stickers the same using LCM of 2 and 3.
LCM of 2 and 3 = 6
Number of blue stickers that Adam gives away
= 3 u - 2 u
= 1 u
1 u = 45
Number of more green stickers than blue stickers at first
= 6 u - 3 u
= 3 u
= 3 x 45
= 135
(b)
Number of less blue stickers than green stickers in the end
= 6 u - 2 u
= 4 u
= 4 x 45
= 180
Answer(s): (a) 135; (b) 180