Adam has 3 times as many blue stickers as red stickers.
After he gives away 50 red stickers,
Adam has 8 times as many blue stickers as red stickers.
- How many more blue stickers than red stickers does Adam have at first?
- How many less red stickers than blue stickers does Adam have in the end?
|
Blue |
Red |
Before |
3 x 8 = 24 u |
1 x 8 = 8 u |
Change |
No Change |
- 50 |
After |
8 x 3 = 24 u |
1 x 3 = 3 u |
(a)
The number of blue stickers remains unchanged.
Make the number of blue stickers and red stickers the same using LCM of 3 and 8.
LCM of 3 and 8 = 24
Number of red stickers that Adam gives away
= 8 u - 3 u
= 5 u
5 u = 50
1 u = 50 ÷ 5 = 10
Number of more blue stickers than red stickers at first
= 24 u - 8 u
= 16 u
= 16 x 10
= 160
(b)
Number of less red stickers than blue stickers in the end
= 24 u - 3 u
= 21 u
= 21 x 10
= 210
Answer(s): (a) 160; (b) 210