Adam has 2 times as many red stickers as green stickers.
After he gives away 36 green stickers,
Adam has 3 times as many red stickers as green stickers.
- How many more red stickers than green stickers does Adam have at first?
- How many less green stickers than red stickers does Adam have in the end?
|
Red |
Green |
Before |
2 x 3 = 6 u |
1 x 3 = 3 u |
Change |
No Change |
- 36 |
After |
3 x 2 = 6 u |
1 x 2 = 2 u |
(a)
The number of red stickers remains unchanged.
Make the number of red stickers and green stickers the same using LCM of 2 and 3.
LCM of 2 and 3 = 6
Number of green stickers that Adam gives away
= 3 u - 2 u
= 1 u
1 u = 36
Number of more red stickers than green stickers at first
= 6 u - 3 u
= 3 u
= 3 x 36
= 108
(b)
Number of less green stickers than red stickers in the end
= 6 u - 2 u
= 4 u
= 4 x 36
= 144
Answer(s): (a) 108; (b) 144