Adam has 5 times as many red stickers as green stickers.
After he gives away 30 green stickers,
Adam has 8 times as many red stickers as green stickers.
- How many more red stickers than green stickers does Adam have at first?
- How many less green stickers than red stickers does Adam have in the end?
|
Red |
Green |
Before |
5 x 8 = 40 u |
1 x 8 = 8 u |
Change |
No Change |
- 30 |
After |
8 x 5 = 40 u |
1 x 5 = 5 u |
(a)
The number of red stickers remains unchanged.
Make the number of red stickers and green stickers the same using LCM of 5 and 8.
LCM of 5 and 8 = 40
Number of green stickers that Adam gives away
= 8 u - 5 u
= 3 u
3 u = 30
1 u = 30 ÷ 3 = 10
Number of more red stickers than green stickers at first
= 40 u - 8 u
= 32 u
= 32 x 10
= 320
(b)
Number of less green stickers than red stickers in the end
= 40 u - 5 u
= 35 u
= 35 x 10
= 350
Answer(s): (a) 320; (b) 350