Adam has 4 times as many blue stickers as red stickers.
After he gives away 35 red stickers,
Adam has 9 times as many blue stickers as red stickers.
- How many more blue stickers than red stickers does Adam have at first?
- How many less red stickers than blue stickers does Adam have in the end?
|
Blue |
Red |
Before |
4 x 9 = 36 u |
1 x 9 = 9 u |
Change |
No Change |
- 35 |
After |
9 x 4 = 36 u |
1 x 4 = 4 u |
(a)
The number of blue stickers remains unchanged.
Make the number of blue stickers and red stickers the same using LCM of 4 and 9.
LCM of 4 and 9 = 36
Number of red stickers that Adam gives away
= 9 u - 4 u
= 5 u
5 u = 35
1 u = 35 ÷ 5 = 7
Number of more blue stickers than red stickers at first
= 36 u - 9 u
= 27 u
= 27 x 7
= 189
(b)
Number of less red stickers than blue stickers in the end
= 36 u - 4 u
= 32 u
= 32 x 7
= 224
Answer(s): (a) 189; (b) 224