Adam has 2 times as many red stickers as blue stickers.
After he gives away 27 blue stickers,
Adam has 3 times as many red stickers as blue stickers.
- How many more red stickers than blue stickers does Adam have at first?
- How many less blue stickers than red stickers does Adam have in the end?
|
Red |
Blue |
Before |
2 x 3 = 6 u |
1 x 3 = 3 u |
Change |
No Change |
- 27 |
After |
3 x 2 = 6 u |
1 x 2 = 2 u |
(a)
The number of red stickers remains unchanged.
Make the number of red stickers and blue stickers the same using LCM of 2 and 3.
LCM of 2 and 3 = 6
Number of blue stickers that Adam gives away
= 3 u - 2 u
= 1 u
1 u = 27
Number of more red stickers than blue stickers at first
= 6 u - 3 u
= 3 u
= 3 x 27
= 81
(b)
Number of less blue stickers than red stickers in the end
= 6 u - 2 u
= 4 u
= 4 x 27
= 108
Answer(s): (a) 81; (b) 108